7x^2=48X+7

Solution for 7x^2=48X+7 equation:

7x^2=48x+7

We move all terms to the left:

7x^2-(48x+7)=0

We get rid of parentheses

7x^2-48x-7=0

a = 7; b = -48; c = -7;
Δ = b2-4ac
Δ = -482-4·7·(-7)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-50}{2*7}=\frac{-2}{14}
=-1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+50}{2*7}=\frac{98}{14}
=7
$